If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-16=-4x
We move all terms to the left:
5x^2-16-(-4x)=0
We get rid of parentheses
5x^2+4x-16=0
a = 5; b = 4; c = -16;
Δ = b2-4ac
Δ = 42-4·5·(-16)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{21}}{2*5}=\frac{-4-4\sqrt{21}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{21}}{2*5}=\frac{-4+4\sqrt{21}}{10} $
| 11r=-22 | | -19-3a=5-4(2a+1) | | 5x^-16=-4x | | 630/x+28=18.50 | | 4x+9+25=180 | | 6r+133=-10r | | 42/x+11=2.6 | | 8(x-3)=26-2x | | -2(3x-4)=12+4x | | 2(3x-11)+5x-23=180 | | -(8b+6)=-6-8b | | -2y+7=-9-y-9y | | -3(x-4=-2(3x+1)= | | 3A+2b=18 | | -3(x-4=-2(3x+1) | | -8+5m=7m-(m+4) | | 232=-8(-5b+6) | | 50=3^x-2 | | 1=4x+9;=-2 | | k=1.54 | | 1u-0=1 | | 2(5m+4)=10m+8-6m | | 85=4(1-7x)-3 | | Y=1.8x+9 | | -2(6p+8)=-100 | | 0.2a+1.6=-0.06 | | -10x+4x=-8x+14 | | 9h+30=120 | | -88=7(1+2x)+3 | | 61=9.6-k | | 61=290/3-k | | 0.7n-1=-4.01 |